△ABC的三边a,b,c的倒数成等差数列,求证B

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△ABC的三边a,b,c的倒数成等差数列,求证B

△ABC的三边a,b,c的倒数成等差数列,求证B
△ABC的三边a,b,c的倒数成等差数列,求证B<π/2

△ABC的三边a,b,c的倒数成等差数列,求证B
证明:
2/b=1/a+1/c
2/sinB=1/sinA+1/sinC
2/sinB=(sinA+sinC)/sinAsinC
∴sinAsinC=-(1/2)[cos(A+C)-cos(A-C)]>0
cos(A+C)-cos(A-C)<0
-cosB-cos(A-C)<0
cosB>cos(C-A)
∵1/c>1/a
a>c
∠A>∠C
C-A<0
cos(C-A)>0
∴cosB>0
B<π/2