作业帮用Mathematica求变化方程time(h) concentrition(mg/L)2.5 30.43645 68.72737.5 75.610 82.472715 82.145520 77.236425 68.727330 68.727335 58.581840 51.381845 50.072750 41.890960 38.618270 35.345580 28.472790 25.2100 18.9818110 15.0545120 12.1091130 11
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用Mathematica求变化方程time(h) concentrition(mg/L)2.5 30.43645 68.72737.5 75.610 82.472715 82.145520 77.236425 68.727330 68.727335 58.581840 51.381845 50.072750 41.890960 38.618270 35.345580 28.472790 25.2100 18.9818110 15.0545120 12.1091130 11
用Mathematica求变化方程
time(h) concentrition(mg/L)
2.5 30.4364
5 68.7273
7.5 75.6
10 82.4727
15 82.1455
20 77.2364
25 68.7273
30 68.7273
35 58.5818
40 51.3818
45 50.0727
50 41.8909
60 38.6182
70 35.3455
80 28.4727
90 25.2
100 18.9818
110 15.0545
120 12.1091
130 11.1273
140 7.2
150 7.2
160 3.92727
这是数据~希望有人能帮我用mathematica求一下浓度随时间变化的方程馁~希望详细一些 我比较笨馁~
哈哈~o(∩_∩)o...
用Mathematica求变化方程time(h) concentrition(mg/L)2.5 30.43645 68.72737.5 75.610 82.472715 82.145520 77.236425 68.727330 68.727335 58.581840 51.381845 50.072750 41.890960 38.618270 35.345580 28.472790 25.2100 18.9818110 15.0545120 12.1091130 11
做直线拟合：Fit[data,{1,x},x]
72.7306 - 0.477302 x
二次和三次的依次是：
75.5695 - 0.610861 x + 0.000873775 x^2
67.3036 + 0.12403 x - 0.0113442 x^2 + 0.0000520347 x^3