z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 19:17:30
z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
dz/dx=arctan(xy)+xy/[1+(xy)^2]
(dz/dx)|(1,1)=π/4+1/2
(dz/dy)|(1,1)=x^2/[1+(xy)^2]=1/2
dz/dx=arctan(xy)+xy/[1+(xy)^2]
(dz/dx)|(1,1)=π/4+1/2
(dz/dy)|(1,1)=x^2/[1+(xy)^2]=1/2
z=x*arctan(xy),求(dz/dx)|(1,1),(dz/dy)|(1,1)
z=arctan(x/y),求dz
设z=arctan(xy),y=e^x ,求dz/dx .
z=arctan(xy),而y=e^x,求dz/dy
设z=arctan(xy)+2x^2+y^2,求dz
z=x^2*arctan(2y/x)求dz
z=arctan(x-y),求dz
全导数:设z=arctan(xy),而y=e*x次方,求dz/dx设z=arctan(xy),而y=e*x次方,求dz/dx,
设z=arctan(xy),y=e的x次方,求dz/dx不是dz/dx=@z/@y *dy/dx吗(@指偏导),为什么直接对z求导呢?那之后的dy/dx怎么求呢?
z=arctan x/(1+y^2),则dz=?
设函数z=arctan(x/y),求全微分dz
z=arctan(x+y)/(1-xy)求dz还有个题 f(x,y)=√(x^2+y^2)则dz 这是要求什么啊 不太明白 谢
z=xy,x=siny,求dz/dy
设z=(x+y)^xy,求dz
z=f(x/y,xy),求dz
z=f(xy,x^y),求dz.
设z=(x+2y)e^xy,求dz
Z=arctan(xy) 而y=e的x次方,则dz/dx=?最好说下过程