sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值

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sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值

sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1
求值

sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值
sin(π+π/6)-cos(π+π/4)cos(-π/2)+1
=-sin(π/6)+cos(π/4)cos(+π/2)+1
=-1/2+cos(π/4)*0+1
=1/2

利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) cosπ/6=(),sinπ=() 怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3cosπ/4cosπ/3-sinπ/4sinπ/3 cos^6(π/8)-sin^6(π/8)=求值,[cos^2(π/8)-sin^2(π/8)][cos^4(π/8)+sin^4(π/8)+cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-cos^2(π/8)sin^2(π/8)]=cos(π/4)[1-[sin^2(π/4)]/4]==7√2/16 cos(-23π/4)+sin(37π/6) cos(-π/4)*sin(5/6π)=? 已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= sin(π+π/6)-cos(π+π/4)cos(-π/2)+1求值 sin(4分之π-β)cosβ+cos(4分之π-β)sinβ= cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的? sin(a-π)+5cos(2π-a)+4cos(π+a)/cos(π-a)-sin(-a) 求 [Sin(6π+a)Cos(7π-a)]/[Sin(3π+a)+Sin(-π+a) 化简sin(A+π/4)sin(A-π/4)/sin^4A-cos^4A 化简sin(π/4+α)cosα-sin(π/4-α)sinα 设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin² θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小