作业帮数学题三道计算(X-2Y+Z)(X+2Y-Z)[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2[(2T+1)^2-(1-2T)^2](T^2-2)
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 15:44:49
![数学题三道计算(X-2Y+Z)(X+2Y-Z)[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2[(2T+1)^2-(1-2T)^2](T^2-2)](/uploads/image/z/296983-55-3.jpg?t=%E6%95%B0%E5%AD%A6%E9%A2%98%E4%B8%89%E9%81%93%E8%AE%A1%E7%AE%97%28X-2Y%2BZ%29%28X%2B2Y-Z%29%5B%281%2F4%29X-%282%2F5%29Y%5D%5E2%2A%5B%281%2F4%29X%2B%282%2F5%29Y%5D%5E2%5B%282T%2B1%29%5E2-%281-2T%29%5E2%5D%28T%5E2-2%29)
数学题三道计算(X-2Y+Z)(X+2Y-Z)[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2[(2T+1)^2-(1-2T)^2](T^2-2)
数学题三道计算
(X-2Y+Z)(X+2Y-Z)
[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2
[(2T+1)^2-(1-2T)^2](T^2-2)
数学题三道计算(X-2Y+Z)(X+2Y-Z)[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2[(2T+1)^2-(1-2T)^2](T^2-2)
(1):(x-2y+z)(x+2y-z)=[x-(2y-z)][x+(2y-z)]=x^2-(2y-z)^2=x^2-4y^2-z^2+4yz;(2):(x/4-2y/5)^2(x/4+2y/5)^2=[(x/4-2y/5)(x/4+2y/5)]^2=(x^2/16-4y^2/25)^2=x^4/256-xy/50+16y^4/625;(3):[(2t+1)^2-(1-2t)^2](t^2-2)=[(2t+1)+(1-2t)][(2t+1)-(1-2t)](t^2-2)=2*4t(t^2-2)=8t^3-16t
数学题三道计算(X-2Y+Z)(X+2Y-Z)[(1/4)X-(2/5)Y]^2*[(1/4)X+(2/5)Y]^2[(2T+1)^2-(1-2T)^2](T^2-2)
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