化简：(sin^2α-tan^2α)/(sin^2α·tan^2α)

化简：(sin^2α-tan^2α)/(sin^2α·tan^2α) 化简：(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα 若a属于(0,π/2)试比较tanα、tan(tanα)、tan(sinα) 已知tanα=2,sinα (cot^2)α((tan^2) α-(sin^2) α) 化简 化简(sin2α+2sin^2α)/(1-tanα) 化简cos^2(-α)-[tan(360°+α)/sin(-α)] 化简cos2(-α)-tan(2π+α)/sin(-α) 化简(sinα)^2tanα+cosα+(cosα)^2*1/tanα+2sinαcosα 化简：(cosα/2-sinα/2)(cosα/2+sinα/2)(1+tanαtanα/2) 化简sin^2α*tanα+cos^2α*1/tanα+2sinα*cosα 化简:sin^2α*tanα+(cos^2α)/(tanα)+2sinαcosα 只要结果 化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α) cos(π-α)tan(2π-α)tan(π-α)/sin(π+α) 化简 化简sin(2π-α）tan（α+π）tan（-α-π）/ 求证tan^2α-sin^2α=tan^2α*sin^2α 数学证明sin^2 αtan^2 α=tan^2 α-sin^2 α 求证:tan^2α-sin^α=tan^2乘sin^2α