谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1)

谁能帮我解一下：log2(x + 1) = 4 - log2(x + 1)log2(x + 1) = 4 - log2(x + 1) 已知函数f（x）=log2（x+1/x-1）+log2（x-1）+log2（p-x） 求函数f（x）的值域,谁能给我讲解一下, 解方程log2(2-x)=log2(x-1)+1 解2log2^(x-5)=log2^(x-1)+1 解不等式：|log2（x-1）|+log2（5-x） 解不等式log2(4x+8)>log2(2x+1) 解方程：log2(x+4)+log2(x-1)=1+log2(x+8) log2(x+1)+log2x=log2（6）解方程 |[log2(x)]^2-3log2(x)+1| log2(x+1)>log2(3-x) log2 (x+1)+log2 x=log6 已知函数f(x)=log2^ ( x/4 ) ×log2^ (2x) (1)解不等式f(x)>0;(2)当x∈【1,4】时,求f(x)的值域f（x）=log2（2x）×log2（x／4）＝[（log2 2）+(log2 x)] ×[(log2 x) -(log2 4)]=[1+(log2 x)] ×[(log2 x) -2]=(log2 x)² - (log2 x) -2 log2(x^2-2)=log2(10x+8)-1 我算不出来. 解不等式log2[1-(1/x)]>1 解不等式：log2(2x-1) 解不等式:log2(x²-1) 解不等式2log2(2^x+1) log2(x+1)=3怎么解