作业帮(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
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(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
首先要知道loga b^n=n*loga b a为底数,b为真数
loga^n b=lg b/(n*lga) a^n为底数,b为真数
原式=（3*lg5/lg2+lg5/lg2+1/3*lg5/lg2）*(lg2/lg5+lg2/lg5+lg2/lg5)
=13/3*lg5/lg2*3*lg2/lg5
=13
log2 20-log4 25
log2 20-log4 25的答案是
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
log4(log2^x)=log2(log4^x)求log2^x
(log2 5+log4 125)log3 2/ log根号3 5
log4^25-2log4^10+log2^9×log3^根号5×log5^2
log2^x=log4^9
2log2为什么等于log4
log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X
log4 243 - log8 729=?log4 12 - log2 6=?
高中数学对数计算求值（log2 125+log4 25+log8 5）*（log125 8+log25 4+log5 2）要用简便运算啊.
关于对数运算（lg5）^2+lg2·lg50=?(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)=?
(log2(5）+log4（125））×log3（2）/log根号3（5）
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
3^log9(25)+16^log4(2)-(根号7)^log7(9)+(-1)^log2(1)