作业帮f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)
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![f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)](/uploads/image/z/11662639-7-9.jpg?t=f%28a%29%3D+2+tana-%5B2%28sina%2F2%29%5E2-1%5D%2F%5B%28sina%2F2%29%28cosa%2F2%29%5D%2C%E6%B1%82f%28%CF%80%2F12%29)
f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)
f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)
f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)
f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)]
=2tana+cosa/(1/2sina)
=2(tana+cota)
=2(sina/cosa+cosa/sina)
=2(sin^2a+cos^2a)/(sinacosa)
=4/sin(2a)
f(π/12)=4/sin(π/6)=8
f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)
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