作业帮求极限lim(x→2)(x^2-3x+2)/(x^2+4x-12)
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求极限lim(x→2)(x^2-3x+2)/(x^2+4x-12)
求极限lim(x→2)(x^2-3x+2)/(x^2+4x-12)
求极限lim(x→2)(x^2-3x+2)/(x^2+4x-12)
lim(x→2)(x^2-3x+2)/(x^2+4x-12)
=lim(x→2)(x-2)(x-1) / (x-2)(x+6)
=lim(x→2) (x-1)/(x+6)
=(2-1) /( 2+6)
=1/8
lim(x→2)(x^2-3x+2)/(x^2+4x-12)
=lim(x→2)(x-2)(x-1)/(x-2)(x+6)
=lim(x→2)(x-1)/(x+6)
=1/8
楼上的思路是罗比达法则，我的思路是消零因子
lim(x→2)(x^2-3x+2)/(x^2+4x-12) (0/0)
=lim(x→2)(2x-3)/(2x+4)
=1/8
lim(x→2) (x^2-3x+2)/(x^2+4x-12)
=lim(x→2) (x-2)(x-1)/[(x-2)(x+6)]
=lim(x→2) (x-1)/(x+6)
=lim(x→2) [1-7/(x+6)]
1/8
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