计算cosπ/12*sinπ/12
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计算cosπ/12*sinπ/12
计算cosπ/12*sinπ/12
计算cosπ/12*sinπ/12
=(1/2)sin π/6
=(1/2)×(1/2)
=1/4
这题是代入sin 2α=2sin αcos α求得的
计算cosπ/12*sinπ/12
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值:sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cos*π/12—sin*π/12
cosπ/12乘以sinπ/12
(cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)等于
(cosπ/12-sinπ/12)(cosπ/12+sinπ/12)的值为
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(sinπ/12+cosπ/12)(sinπ/12-cosπ/12)=
计算sin²π/8-cos²π/8=
sinπ/8cosπ/8根据什么公式计算?
计算,sin(π/12)-sin(5π/12)+2sin(π/8)sin(3π/8)
已知α=7/12π,那么cosα√(1-sinα)/(1+sinα)+sinα√(1-cosα)/(1-cosα)=
cos^2π/12-sin^2π/12等于