(x+t )(x-6)-(x-2)(x+1)(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)，其中x=1/2

来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 00:17:14
(x+t )(x-6)-(x-2)(x+1)(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)，其中x=1/2

(x+t )(x-6)-(x-2)(x+1)(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)，其中x=1/2
(x+t )(x-6)-(x-2)(x+1)
(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)，其中x=1/2

(x+t )(x-6)-(x-2)(x+1)(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)，其中x=1/2
(x^3+2)^2-(x^3-2)^2-2(x+2)(x-2)(x^2+4)
= x^6 + 4x^3 + 4 - ( x^6 - 4x^3 + 4) - 2(x^2 - 4)(x^2 + 4)
= x^6 + 4x^3 + 4 - x^6 + 4x^3 - 4 - 2(x^4 - 16)
= 8x^3 - 2x^4 + 32
= - 2x^4 + 8x^3 + 32
当x = 1/2时,
原式= -2×(1/2)^4 + 8×(1/2)^3 + 32
= - 1/8 + 1 + 32
= 32又7/8

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