x/(y+z)=y/(x+z)=z/(x+y)x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2y/(x+z)=z/(x+y)=(y-z)/【(x+z)-(x+y)】=-1我知道这是两种情况做法一是x+y+z≠0做法二是x+y+z=0我的疑问是做法二在证明中那里用到了

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 21:00:04
x/(y+z)=y/(x+z)=z/(x+y)x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2y/(x+z)=z/(x+y)=(y-z)/【(x+z)-(x+y)】=-1我知道这是两种情况做法一是x+y+z≠0做法二是x+y+z=0我的疑问是做法二在证明中那里用到了

x/(y+z)=y/(x+z)=z/(x+y)x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2y/(x+z)=z/(x+y)=(y-z)/【(x+z)-(x+y)】=-1我知道这是两种情况做法一是x+y+z≠0做法二是x+y+z=0我的疑问是做法二在证明中那里用到了
x/(y+z)=y/(x+z)=z/(x+y)
x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2
y/(x+z)=z/(x+y)=(y-z)/【(x+z)-(x+y)】=-1
我知道这是两种情况做法一是x+y+z≠0
做法二是x+y+z=0
我的疑问是做法二在证明中那里用到了x+y+z=0

x/(y+z)=y/(x+z)=z/(x+y)x/(y+z)=y/(x+z)=z/(x+y)=(x+y+z)/[(x+z)+(x+y)+(y+z)]=1/2y/(x+z)=z/(x+y)=(y-z)/【(x+z)-(x+y)】=-1我知道这是两种情况做法一是x+y+z≠0做法二是x+y+z=0我的疑问是做法二在证明中那里用到了
x+y+z=0
所以第一种分母为0,不能用
所以此时就换了一种方法