是-1/3X+1/4X=1

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是-1/3X+1/4X=1

是-1/3X+1/4X=1
是-1/3X+1/4X=1

是-1/3X+1/4X=1
-1/12

七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 4/x+4=3/x+1/x+124/x+4=3/x+1/x+12,x+4和x+12是分母, =(x^2-5x+4)(x^2-5x+6) =(x^2-5x)^2+10(x^2-5x)+24 是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24不好意思我弄错了,是=(x^2-5 设x-1/x=3,求(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)答案是119/110 (x+1)(x+3)=x^2是一元二次方程吗?11x^4-6x^3+2x^2=2+11x^4-6x^3 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 x>0 f(x)=(x+1/x)^4-(x^4+1/x^4)//x+1/x^3-(x^3+1/x^3)的值域(x+1/x)^4-(x^4+1/x^4)是分子 x+1/x^3-(x^3+1/x^3)是分母 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x左边是怎么变成右边的形式的? (X-1)(X-2)=X*X-3X+2 X*X-3X+2=(X-1)(X-3) X*X+4X+4=X(X-4)+4 X*X+Y*Y=(X+Y)(X-Y) 哪一个因式分解是正确的 =(x^2-5x)^2+10(x^2-5x)+24 =x^4-10x^3+25x^2+10x^2-50x+24 这是怎么转化的(X-1)(X-2)(X-3)(X-4) =(X-1)(X-4) (X-2)(X-3)=(x^2-5x+4)(x^2-5x+6)=(x^2-5x)^2+10(x^2-5x)+24=x^4-10x^3+25x^2+10x^2-50x+24=x^4-10x^3+35x^2-50x+24 X>4是1/X