sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)

来源：学生作业帮助网编辑：作业帮时间：2024/04/30 07:34:26

sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)
sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)

sin²(-α)·cos(π+α)/tan(2∏+α)tan(∏+α)cos³(-∏-α)
原式=sin²α·(-cosα)/tanαtanα(-cos³α)
=sin²αcosα/(sin²α/cos²α*cos³α)
=1