作业帮计算：1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 17:54:44
![计算：1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]](/uploads/image/z/620398-46-8.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A1-%5Ba-+1%2F%EF%BC%881-a%EF%BC%89%5D%26%23178%3B%C3%B7%5B%EF%BC%88a%26%23178%3B-a%2B1%EF%BC%89%2F%EF%BC%88a%26%23178%3B-2a%2B1%EF%BC%89%5D)
计算：1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]
计算：1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]
计算：1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]
1-[a- 1/（1-a）]²÷[（a²-a+1）/（a²-2a+1）]
=1-[a(1-a)/(1-a)-1/(1-a)]²÷[（a²-a+1）/（a-1）²]
=1-(a²-a+1)²/(a-1)²×（a-1）²/（a²-a+1）
=1-(a²-a+1)
=-a²+a
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