作业帮求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]的最大值
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/13 15:17:24
![求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]的最大值](/uploads/image/z/5302804-4-4.jpg?t=%E6%B1%82%5B%28k-10%29%26%23178%3B%282k-1%29%26%23178%3B%2B%28k-10%29%26%23178%3B%28k%2B2%29%26%23178%3B%5D%2F%5B%282k-1%29%5E4%2B%28k%2B2%29%5E4%5D%E6%B1%82%5B%28k-10%29%26%23178%3B%282k-1%29%26%23178%3B%2B%28k-10%29%26%23178%3B%28k%2B2%29%26%23178%3B%5D%2F%5B%282k-1%29%5E4%2B%28k%2B2%29%5E4%5D%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC)
求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]的最大值
求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]
求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]的最大值
求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]求[(k-10)²(2k-1)²+(k-10)²(k+2)²]/[(2k-1)^4+(k+2)^4]的最大值
把这个式子当做一个函数,求出它的导数,导数等于0的时候有可能就是它的最大值,也有可能是最小值,需要按导数等于0的点列出几个区间求出导数的正负,先正后负的那个点就有可能是最大值.