main() {int x=40,y=4,z=4; x = y = =z; printf(“%d”,x); x = x = = (y-z); printf(“%d”,x);} D.1 0

#include int main(){ int x=0,y=0; while(x #include int call(int s[],int y) { static int t=3; y=s[t--]; return(y); } void main() { in#includeint call(int s[],int y){static int t=3;y=s[t--];return(y);}void main(){int a[]={3,8,4,2},n,x=0;for(n=0;n C语言 答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} #includevoid f(int y,int *x){ y=y+*x; *x=*x+y;} void main(){ int x=2,y=4;f(y,&x);printf(%d,%d ,x,y);} void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y=4; f(y,&x); printf(%d %d ,x,y); } void f( int y,int *x){y=y+*x; *x=*x+y;}main( ){ int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} 执行后输出的结果是 . void fun(int *x,int y){printf(%d%d,*x,*y);*x=3;*y=4;}main(){int x=1,y=2;fun(&y,&x);printf(%d%d,x,y);} main(){ int x=5; while(x #include #include int main() { int x,y,sqrt; scanf (%d,&x); y=sqrt(x); if (x> #include using namespace std; int main() { int a,b,c; a=3; int f(int x,int y,int z);#include using namespace std; int main() {int a,b,c;a=3;int f(int x,int y,int z); cin>>a>>b>>c;c=f(a,b,c);cout # include void p(int *x,int y){ ++*x; y=y+2; } void main() { int x=2,y=3; p(&y,y); printf(# includevoid p(int *x,int y){++*x;y=y+2;}void main(){int x=2,y=3;p(&y,y);printf(%d#%d,x,y);} main() { int x=2002,y=2003; printf(%d ,(x,y)); } 为什么结果是2003? main() { int x=2002,y=2003; printf(%d ,(x,y)); } 求高手解释一下这段程序#include class Test {int x,y; public: Test(int i,int j=0) {x=i;y=j;} int get(int i,int j) {return i+j;} }; void main() {Test t1(2),t2(4,6); int (Test::*p)(int,int=10); p=Test::get; cout int func(int x,int y ) { return(x+y) } main() {int a=1,b=2,c=3,d=4,e=5;printf(&d ,func((a+b,b+c,c+a),(d+e))); #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf(a=%d,x=%d ,a, main(){int a[]={2,4,6,8,10};int y=1,x,*p;p=&a[1];for(x=0;x #include main() {int x,y=0,i; for(x=11;x