lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可：lim(x→∞)[(x^2-2x+1)/(x+1)]=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]我不知道下面这一步是怎么得来的:=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]x^

Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 x/2-1lim(1-2/x)x→∞ lim(x→∞)(1-2/x)^2x lim(x→∞)(1-2/x) (x+1)次方 lim(x→∞)[1+(1/x)]^x/2 lim x→∞(2x+1)/(3x-4) lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= 求lim(√x^2+1)-x x→-∞ 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim xsin(2/x) x→∞ lim x→1 x-1/x^2-x lim(x→0)e^x-x-1/x^2 lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(2x^3-x^2-3)/(x^3-x+1)