解一元二次方程：x²+2mx-3nx-3m²-mn+2n²=0

解一元二次方程：x²+2mx-3nx-3m²-mn+2n²=0
解一元二次方程：x²+2mx-3nx-3m²-mn+2n²=0

解一元二次方程：x²+2mx-3nx-3m²-mn+2n²=0
方程化简,得
x^2+(2m-3n)x+(2n-3m)(n+m)=0
因式分解,得
（x-2n+3m）(x-m-n)=0
所以方程两根为——
x1=2n-3m x2=m+n

x²+2mx-3nx-3m²-mn+2n²=0
x²+(2m-3n)x-(m+n)(3m-2n)=0
(x+3m-2n)(x-m-n)=0
x1=-3m+2n x2=m+n