f(x)=sin²ωx+sinωxcosωx的化简

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f(x)=sin²ωx+sinωxcosωx的化简

f(x)=sin²ωx+sinωxcosωx的化简
f(x)=sin²ωx+sinωxcosωx的化简

f(x)=sin²ωx+sinωxcosωx的化简
由三角函数倍角公式,可化简为:
f(x)=sin²ωx+sinωxcosωx
=1/2(1-cos2ωx)+1/2*2sinωxcosωx
=1/2sin2ωx-1/2cos2ωx+1/2
=√2/2sin(2ωx-π/4)+1/2

f(x)=sin²ωx+sinωxcosωx
=1/2(1-cos2ωx)+1/2*2sinωxcosωx
=1/2sin2ωx-1/2cos2ωx+1/2
=√2/2sin(2ωx-π/4)+1/2