作业帮int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)); printf("%d ",* *k); 为什么?输出结果是（2、4 ）.
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/07 07:23:03
![int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf(](/uploads/image/z/3648338-26-8.jpg?t=int+a%5B5%5D%3D%7B2%2C4%2C6%2C8%2C10%7D%2C%2AP%2C%2A+%2Ak%3B+p%3Da%3B+k%3D%26p%3B+printf%28%22%25d%22%2C%2A%28p%2B%2B%29%29%3B+printf%28%22%25d+%22%2C%2A+%2Ak%29%3B+%E4%B8%BA%E4%BB%80%E4%B9%88%3F%E8%BE%93%E5%87%BA%E7%BB%93%E6%9E%9C%E6%98%AF%EF%BC%882%E3%80%814+%EF%BC%89.)
int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)); printf("%d ",* *k); 为什么?输出结果是（2、4 ）.
int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)); printf("%d ",* *k); 为什么?
输出结果是（2、4 ）.
int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)); printf("%d ",* *k); 为什么?输出结果是（2、4 ）.
P++,先把P赋值出去,自己再增.printf("%d",*(p++));
等同于：printf("%d",*(p));P++；p是数组a的首地址,因此输出a【0】即,2,
同样,k输出p++后的a【1】,即4