作业帮已知m,n满足(m-2)²+|½n+1|=0.求[(3m-n)²-(2m+n)²+5m(m-n)]÷5m的值
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![已知m,n满足(m-2)²+|½n+1|=0.求[(3m-n)²-(2m+n)²+5m(m-n)]÷5m的值](/uploads/image/z/1811536-16-6.jpg?t=%E5%B7%B2%E7%9F%A5m%2Cn%E6%BB%A1%E8%B6%B3%28m-2%29%26%23178%3B%2B%7C%26%23189%3Bn%2B1%7C%3D0.%E6%B1%82%5B%283m-n%29%26%23178%3B-%282m%2Bn%29%26%23178%3B%2B5m%28m-n%29%5D%C3%B75m%E7%9A%84%E5%80%BC)
已知m,n满足(m-2)²+|½n+1|=0.求[(3m-n)²-(2m+n)²+5m(m-n)]÷5m的值
已知m,n满足(m-2)²+|½n+1|=0.求[(3m-n)²-(2m+n)²+5m(m-n)]÷5m的值
已知m,n满足(m-2)²+|½n+1|=0.求[(3m-n)²-(2m+n)²+5m(m-n)]÷5m的值
已知m,n满足(m-2)²+|½n+1|=0
所以m-2=0,½n+1=0
所以m=2,n=-2
所以[(3m-n)²-(2m+n)²+5m(m-n)]÷5m
=[(3*2+2)²-(2*2-2)²+5*2(2+2)]÷(5*2)
=(64-4+40)÷10=10