若a的平方+b的平方=1,ab=25分之12,则a+b=__;a的三次方-b的三次方= ;a的四次方-不得四次方= ;a的六次方-b的六次方= ;

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若a的平方+b的平方=1,ab=25分之12,则a+b=__;a的三次方-b的三次方= ;a的四次方-不得四次方= ;a的六次方-b的六次方= ;

若a的平方+b的平方=1,ab=25分之12,则a+b=__;a的三次方-b的三次方= ;a的四次方-不得四次方= ;a的六次方-b的六次方= ;
若a的平方+b的平方=1,ab=25分之12,则a+b=__;
a的三次方-b的三次方= ;
a的四次方-不得四次方= ;
a的六次方-b的六次方= ;

若a的平方+b的平方=1,ab=25分之12,则a+b=__;a的三次方-b的三次方= ;a的四次方-不得四次方= ;a的六次方-b的六次方= ;
a²+b²=1
ab=12/25

(a-b)²=a²+b²-2ab
=1-2×12/25
=1/25
a-b=±1/5
(a+b)²=a²+b²+2ab
=1+2×12/25
=49/25
a+b=±7/5

a³-b³=(a-b)(a²+ab+b²)
=±1/5×(1+12/25)
=±37/125

a^4-b^4
=(a-b)(a+b)(a²+b²)
=±1/5*(±7/5)*1
=±7/25

a^6-b^6
=(a^3-b^3)(a^3+b^3)
=±37/125*(a+b)(a²-ab+b²)
=±37/125*(±7/5)*(1-12/25)
=±37/125*(±7/5)*13/25
=±3367/15625

∵ a ² + b ² = 1 ,a b = 12 / 25
∴ (a + b)² = a ² + 2 a b + b ²
= 1 + 2 × 12 / 25
= 1 + 24 / 25
...

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∵ a ² + b ² = 1 ,a b = 12 / 25
∴ (a + b)² = a ² + 2 a b + b ²
= 1 + 2 × 12 / 25
= 1 + 24 / 25
= 49 / 25
∴ a + b = ± √49 / 25 = ± 7 / 5
a ³ - b ³ = (a - b)(a ² + a b + b ²)
∵ (a - b)² = a ² - 2 a b + b ²
= 1 - 2 × 12 / 25
= 1 - 24 / 25
= 1 / 25
∴ a - b = ± √1 / 25 = ± 1 / 5
① 当 a - b = 1 / 5 时,则:a ³ - b ³ = (a - b)(a ² - a b + b ² )
= 1 / 5 × (1 - 12 / 25)
= 1 / 5 × 13 / 25
= 13 / 125
② 当 a - b = - 1 / 5 时,则: a ³- b ³ = (a - b)(a ² - a b + b ² )
= - 1 / 5 × (1 - 12 / 25)
= - 1 / 5 × 13 / 25
= - 13 / 125
a ^ 4 - b ^ 4 = (a ² + b ²)(a ² - b ²)= (a ² + b ²)(a + b)(a - b)
①当 a + b = 7 / 5 , a - b = 1 / 5 时,则:(a ² + b ²)(a + b)( a - b)
= 1 × 7 / 5 × 1 / 5
= 7 / 25
②当 a + b = 7 / 5 , a - b = - 1 / 5 时,则:(a ² + b ²)(a + b)( a - b)
= 1 × 7 / 5 × (- 1 / 5)
= - 7 / 25
③当 a + b = 7 / 5 , a - b = 1 / 5 时,则:(a ² + b ²)(a + b)( a - b)
= 1 × (- 7 / 5) × 1 / 5
= - 7 / 25
④当 a + b = 7 / 5 , a - b = 1 / 5 时,则:(a ² + b ²)(a + b)( a - b)
= 1 × (- 7 / 5) ×(- 1 / 5)
= 7 / 25
综上,a ^ 4 - b ^ 4 = ± 7 / 25

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a+b
=√(a²+b²+2ab)
=√(1+2×12/25)
=√(49/25)
=7/5
a-b
=√(a²+b²-2ab)
=√(1-2×12/25)
=√(1/25)
=1/5
a^3-b^3
=(a-b)(a^2+ab+b^2)
=1/5×(1+12/2...

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a+b
=√(a²+b²+2ab)
=√(1+2×12/25)
=√(49/25)
=7/5
a-b
=√(a²+b²-2ab)
=√(1-2×12/25)
=√(1/25)
=1/5
a^3-b^3
=(a-b)(a^2+ab+b^2)
=1/5×(1+12/25)
=37/125
a^4-b^4
=(a^2+b^2)(a^2-b^2)
=(a^2+b^2)(a+b)(a-b)
=1×7/5×1/5
=7/25
a^6-b^6
=(a^3+b^3)(a^3-b^3)
=(a+b)(a^2-ab+b^2)(a^3-b^3)
=1×(1-12/25)×(37/125)
=13/25×37/125
=481/3125

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