http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面（符号有点小请见谅）.

来源：学生作业帮助网编辑：作业帮时间：2024/05/10 07:42:14

http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面（符号有点小请见谅）.
http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg
题目在上面（符号有点小请见谅）.

http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面（符号有点小请见谅）.
[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)(x+1)-(2x-1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-1-2x+1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-2x]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]*(x+1)/(x^2-2x)*[2x/(x-1)]^2
=[x(x-2)/(x-1)]*1/x(x-2)*[2x/(x-1)]^2
=[1/(x-1)]*[2x/(x-1)]^2
=4x^2/(x-1)^3
(2a/b)^3/[a/(a-b)]-(a/b)/(b/4)
=(2a/b)^3*(a-b)/a-(a/b)*4/b
=8a^3/b^3*(a-b)/a-4a/b^2
=8a^2/b^3*(a-b)-4a/b^2
=8a^2(a-b)/b^3-4a/b^2
=[8a^2(a-b)-4ab]/b^3
=4a[2a(a-b)-b]/b^3
=4a(2a^2-2ab-b)/b^3

[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)...

全部展开

[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-1-2x+1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-2x]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]*(x+1)/(x^2-2x)*[2x/(x-1)]^2
=[x(x-2)/(x-1)]*1/x(x-2)*[2x/(x-1)]^2
=[1/(x-1)]*[2x/(x-1)]^2
=4x^2/(x-1)^3
(2a/b)^3/[a/(a-b)]-(a/b)/(b/4)
=(2a/b)^3*(a-b)/a-(a/b)*4/b
=8a^3/b^3*(a-b)/a-4a/b^2
=8a^2/b^3*(a-b)-4a/b^2
=8a^2(a-b)/b^3-4a/b^2
=[8a^2(a-b)-4ab]/b^3
=4a[2a(a-b)-b]/b^3
=4a(2a^2-2ab-b)/b^3

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