$a = 0; $b = 0; if (($a=3)||($b=3)) { $a++; $b++; } echo $a; echo $b;为什么是 4,1

a=b=c=0;x=35; if(!a)x--;else if(b);if(c)x=3;else x=4 中的 if(!a) if(b) if(c)的意思是什么 if((a=b)>0)t=a;是什么意思 a=1;b=0; if((a++>++b)?a++:b--) a+=b; a值为 int a =1,b=0; if(--a) b++; else if (a=0)b+=2; else b+=3; b等于多少 int a,b,c,t=0; scanf(%d%d%d,&a,&b,&c); if(a>b) { t=a; a=b; b=t; } if(b>c) { t=b; b=c; c=b; } if(along a,b,c,t=0; scanf(%d%d%d,&a,&b,&c); if(a>b) { t=a; a=b; b=t; } if(b>c) { t=b; b=c; c=b; } #include int main ( void ){__int64 a,b;while ( scanf ( %I64X %I64X,&a,&b ) = EOF ){b += a;if ( b < 0 ){b = -b;a = '-';}elsea = 0;if ( a )putchar ( a );printf ( %I64X ,b );}return 0;}b += a;if ( b < 0 ){b = -b;a = '-';}elsea = 0;if ( a )putchar ( C语言 a=b=c=0;x=35 if(!a)x--;a=b=c=0;x=35 if(!a)x--;else if (b);if(c)x=3;else x=4; a=b=c=0;x=35; if a) x--; else if (b); if (c) x=3; else x=4; x等多少 A=2:b=1:c=0 if a then if b then if c then Print “1” else Print “2” else Print “3” else Print #include main(){int a=1,b=0; if(!a)b++; else if (a==0) if(a) b+=2; else b+=3; printf(b) if(a>b&&a-10>=0&&b-10>=0)break是什么意思 [求助] 函数突破了7层,如何换种方法表示 ?=IF(X3>0,A,IF((W3+V3)>0,B,IF((T3+U3)>0,C,IF(S3>0,D,IF(R3>0,E,IF(Q3>0,F,IF(O3>0,G,IF(N3>0,H,IF(M3>0,I,IF(L3>0,J,IF(K3>0,K,IF(J3>0,L,IF(I3>0,M,)))))))))))))))))函数突 IF函数的嵌套问题公式如下：if(G8=岗位A,IF(BN8>=12000,6.5%,IF(BN8>=8000,6%,IF(BN8>=4000,5%,0))),if(G8=岗位B,IF(BO8>=12000,2%,IF(BO8>=8000,1.5%,IF(BO8>=4000,1%,0)))),if(G8=岗位C,IF(BO8>=20000,7%,IF(BO8>=7000,4%,0))),if(G8=岗位 if语句的不理解if(x=0)y=4*x;这个执行条件成立的语句.由小到大输出3个整数.if(a>b){t=a;a=b;b=t;}if(a>c){t=a;a=c;c=t;}if(b>c){t=b;b=c;c=t;}printf(%d,%d,%d,a,b,c);为什么3个if都执行?上面只执行成立的if语句. =if({1,0},B:B,A:A) 这个公式如何理解? #includevoid main(){int a,b,c,max,min;for(a=0;ac>b){max=a;min=b;}if(b>a>c){max=b;min=c;}if(b>c>a){max=b;min=a;}if(c>a>b){max=c;min=b;}if(c>b>a){max=c;min=a;}if(max-min==9)continue;printf(%d%d%d,a,b,c);printf( );}}}}我做的是这样的,怎么才 关于最大公约数的算法int gcd(int a,int b){ int t = 0; int c = 0; if(a==0) return b; if(b==0) return a; if(a < b) { t=a; a=b; b=t; } c = a % b; while(c != 0) { a = b; b = c; c = a % b; } return b; }-- a=1 b:if a