sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)求化简过程.

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sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)求化简过程.

sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)求化简过程.
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
求化简过程.

sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)求化简过程.
原式=sin(x+π/3)+√3cos(x+π/3)+2sin(x-π/3)
=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)
=2sin(x+π/3+π/6)+2sin(x-π/3)
=2[sin(x+π/2)+sin(x-π/3)]
=2(cosx+√3/2sinx-1/2cosx)
=2(√3/2sinx+1/2cosx)
=2sin(x+π/6)

cos(2π/3-x)=cos(π/3+x)关键就是这一步