① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 03:06:36
① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0

① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0
① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0

① ﹙2y+1﹚2-8﹙2y+1﹚+15=0②x2-2√2x+2=0③2y2-2√2y-3=0④2x2-6x+1=0⑤3x2+8x-1=0

4y+2-16y-8+15=0 所以-12y+9=0 所以y=3/4

X‘’-2√2x+(√2)"=0  所以(x-√2)''=0   所以x=√2

化为 (√2)''x''-2√2y-3=0  变为(√2y+1)(√2y-3)=0 所以 y=-√2/2  y=3√2/2
没时间了,