x²-2x-3＜0

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X+X-1=0,求X*X*X+2*X*X+3的值.解X*X*X+2X*X+3=X*X*X+X*X-X+X*X+X+3=X{X*X

设f(x)=x㏑(1+x^2),x≥0.(x^2+2x-3)e^(-x),x＜0,求∫f(x)dx设f(x)=x㏑(1+x^2),x≥0.(x^2+2x-3)e^(-x),x＜0,求∫f(x)dx设f

（x方-3x+2)(-x方+2x+3）＜0,求x解集（x方-3x+2)(-x方+2x+3）＜0,求x解集（x方-3x+2)(-x方+2x+3）＜0,求x解集两边乘-1(x²-3x+2)(x&

x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^

x²-3x-18＜0（x-1)(x+2)=(x-2)(2x+1)x²-3x-18＜0（x-1)(x+2)=(x-2)(2x+1)x²-3x-18＜0（x-1)(x+2)=

3x-2x+1＜03x-2x+1＜03x-2x+1＜0b^2-4ac无解3（x^2-2/3x+1/3)=3(x-1/3)^2+2/3恒大于0,故X无解希望能解决您的问题.

证明f（x）={x-2x+3（x＞0）0（x=0）-x-2x-3（x＜0）｝是奇函数证明f（x）={x-2x+3（x＞0）0（x=0）-x-2x-3（x＜0）｝是奇函数证明f（x）={x-2x+3（x

证明f（x）={x-2x+3（x＞0）0（x=0）-x-2x-3（x＜0）｝是奇函数证明f（x）={x-2x+3（x＞0）0（x=0）-x-2x-3（x＜0）｝是奇函数证明f（x）={x-2x+3（x

两道有关符号问题题目｜x=2｜+｜x-3｜x+2=0x=-2x-3=0x=3x＜-2-x-2-x-3=-2x=1x＞3x+2+x-3=2x-1-2≤x≤3x=2-x+3=5｜x-1｜+｜x+1｜x-1

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x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)x(x*x-6x-9)-x(x*x-8x-15)+2x(3-x)前面多项

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lim(x->0)((2-x)/(3-x))^1/xlim(x->0)((2-x)/(3-x))^1/xlim(x->0)((2-x)/(3-x))^1/xlim(x->0)((2-x)/(3-x))

(x-2)(x-4)+4x(x-3)=0(x-2)(x-4)+4x(x-3)=0(x-2)(x-4)+4x(x-3)=0解(x-2)(x-4)+4x(x-3)=0x²-6x+8+4x

(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0(x+2)(x-3)(x-6)(x-1)=0有种方法叫做穿针引线法,需要在纸上画出函数的简图,这个题的答案应该是

已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值已知1+x+

如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值,如果

七年级下册政治复习提纲(山东人民出版社)第五单元是青春的脚步青春的气息别弄错了啊!格式：XXXXXXXXX1、XXXXXXXXXX.2、XXXXXXXXX.3、XXXXXXXXXXX.七年级下册政治复

(x-2)(x-3)/(x+5)(x-7)＞0(x-2)(x-3)(x+2)(x+3)＞0(x-2)(x-3)/(x+5)(x-7)＞0(x-2)(x-3)(x+2)(x+3)＞0(x-2)(x-3)

1/(x*x-2x-3)+2/(x*-x-6)+3/(x*x+3x+2)=01/(x*x-2x-3)+2/(x*-x-6)+3/(x*x+3x+2)=01/(x*x-2x-3)+2/(x*-x-6)+